- #1
yoda2026
- 11
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any help would be much appreciated
i am trying to calculate the inductance and impedance of a unknown air cored inductor. over a set frequency range (1600hz - 2700hz in 100hz increments) using a series RL circuit
tools
scope
multimeter
frequence generator
Amplifier
1ohm 100W metal clad resistor(1.07ohms under test)
what i have done so far is
frequency generator is set at 1600hz
the output of a frequency generator is connected to the input of the amplifier
the output of the amplifier is used as the power-source
the positive terminal of the amplifier goes to side a of the inductor, side b of the inductor is connected to side a of the resistor, then side b of the resistor is connected to the negative terminal of the amplifier (if this is unclear please see the attached photo)
as a table of data i have (for this i am using the 1600hz information)
frequency = 1600hz
resistor = 1.07Ohms
voltage across the resistor = 0.84V
voltage across the inductor (voltage from the negative terminal of the amplifier to the inductor terminal) = V1-V2 = 0.19V
using this information how do i calculate the inductance
i am trying to calculate the inductance and impedance of a unknown air cored inductor. over a set frequency range (1600hz - 2700hz in 100hz increments) using a series RL circuit
tools
scope
multimeter
frequence generator
Amplifier
1ohm 100W metal clad resistor(1.07ohms under test)
what i have done so far is
frequency generator is set at 1600hz
the output of a frequency generator is connected to the input of the amplifier
the output of the amplifier is used as the power-source
the positive terminal of the amplifier goes to side a of the inductor, side b of the inductor is connected to side a of the resistor, then side b of the resistor is connected to the negative terminal of the amplifier (if this is unclear please see the attached photo)
as a table of data i have (for this i am using the 1600hz information)
frequency = 1600hz
resistor = 1.07Ohms
voltage across the resistor = 0.84V
voltage across the inductor (voltage from the negative terminal of the amplifier to the inductor terminal) = V1-V2 = 0.19V
using this information how do i calculate the inductance