Calculating Initial Velocity of a Projectile

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Discussion Overview

The discussion revolves around calculating the initial velocity of a projectile given the force applied, the mass of the projectile, and the angle of launch, while assuming negligible air resistance. Participants explore the implications of Newton's laws and the relationship between force, momentum, and time in the context of projectile motion.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant inquires whether it is possible to determine the initial velocity of a projectile using the applied force (47N), mass (0.04kg), and launch angle (30 degrees).
  • Another participant suggests that the angle does not affect the initial velocity and proposes using Newton's second law, equating force to the change in momentum.
  • A participant expresses confusion regarding the application of Newton's second law, noting the absence of time or velocity in their calculations.
  • One participant acknowledges the confusion and suggests that the force might have been misinterpreted as Newton-seconds, indicating a need for time to calculate the initial velocity.
  • A later reply describes an experiment involving a spring to fire projectiles, detailing the measurements taken and calculations performed to estimate the initial velocity, while seeking verification of the results.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to calculate the initial velocity, with some expressing uncertainty about the application of concepts and others offering differing interpretations of the problem.

Contextual Notes

Participants mention the need for time in calculations and the potential misinterpretation of force units, indicating limitations in the assumptions made during the discussion.

Who May Find This Useful

Students and individuals interested in projectile motion, Newton's laws, and experimental physics may find this discussion relevant.

jackanese
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is it possible to find the initial velocity of a projectile if you only know the Force applied (47N) to the projectile and the mass (0.04kg) of the projectile (assuming air resistance is negligible).. oh and the angle it was fired at was 30 degrees..

thanks in advance
 
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Good ol' Newton again!

(Angle doesn't matter - the initial velocity will be the same for any angle!)

Just use good ol' Newton's second law: force = change in momentum (and initial momentum is zero). :smile:
 
im sorry i am not following
Newtons second law is basically impulse... which is (delta) momentum / time
but i don't have time or velocity...
can you please clarify...your help is much appreciated
 
Yes, you're right

jackanese said:
but i don't have time or velocity...

oops! I read your initial question as 47 Newton-seconds. :redface:

Yes, you're right. The question says 47 Newtons, so you do need to know the time.

(It must surely be Newton-seconds? - no-one in their right mind would fire a projectile with anything other than an impulse! :smile:)

Try it again, assuming that the total force is 47 Newton-seconds! :smile:
 
ok will do
 
ok so i just ran a few calculations and i came out with a number... not sure if it is correct because my knowledge of physics is pretty limited...

well first i better explain the experiment i am doing (well yeah i guess it is homework and sorry to the mods for putting it in the section but it was never meant to tern into an explanation) .
i was using a spring to fire projectiles and measure the distance and a bunch of other stuff... but i wanted to find the distance i would get if there was no air resistance (so that i could match it against my results)...

anyways what i did was measure the distance the projectile was in contact with the firing pin(this was .14m). i used that in the impulse formula (using the .14m as the displacement, in velocity) and i worked out the time to be .011sec (the time it was in contact with the pin (well actually it was a bolt)).. anyways i used that time and displacement to work out the velocity (.14/.011) which equaled 12.7m/s... now to me that look like the figure i was expecting but i am not sure if the way i got it is correct.

could anyone verify if it is correct or a load of BS..

thanks a lot tiny tim for your help
 

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