Calculating Jet Plane's Acceleration After Full Throttle

  • Thread starter Thread starter Allura
  • Start date Start date
  • Tags Tags
    Acceleration Jet
Click For Summary

Homework Help Overview

The problem involves a jet plane accelerating from an initial speed of 300 m/s to a final speed of 400 m/s over a distance of 2 km. The context is within kinematics, specifically focusing on constant acceleration.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to find time to solve for acceleration and explore various kinematic equations. Some express uncertainty about how to proceed without time being provided.

Discussion Status

There are multiple attempts to apply kinematic equations, with some participants suggesting specific formulas while others question the necessity of time in the calculations. A few participants have shared their calculations, but there is no consensus on the correct approach yet.

Contextual Notes

Participants note the absence of time as a given variable, which complicates the application of certain kinematic equations. There is also mention of previous attempts yielding incorrect results.

Allura
Messages
23
Reaction score
0

Homework Statement



A jet plane is cruising at 300 m/s when suddenly the pilot turns the engines up to full throttle. After traveling 2 km, the jet is moving with a speed of 400 m/s. What is the jet's acceleration (in m/s/s) during this interval assuming the acceleration to be constant?


Homework Equations



I was thinking that in order to go further you would have to solve for the seconds? So I used v=m/s and solved for s, which was then 5s. But I'm not sure where to go from there?

Help?
 
Physics news on Phys.org
Initial and final velocities are given. Displacement is given. Find the kinematic equation which relates Vi, Vf, x and a. And solve for a.
 
But the only kinematic formulas I find include time, which isn't given.
 
Well, I tried vf=vi+a(t) but I got 20m/s/s, which was wrong.
 
Allura said:
Well, I tried vf=vi+a(t) but I got 20m/s/s, which was wrong.

v2f - v2i = 2as

Substitute the values and find a. Here s = 2000 m.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
16
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K