Calculating M and the Unit Digit of M^2003

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Discussion Overview

The discussion revolves around calculating the value of $$M$$ defined by a specific expression involving a real number $$x$$, and determining the unit digit of $$M^{2003}$$. The scope includes mathematical reasoning and problem-solving related to algebra and modular arithmetic.

Discussion Character

  • Mathematical reasoning
  • Exploratory
  • Homework-related

Main Points Raised

  • Participants define $$M$$ as $$M=\frac{3x-1}{1+x}-\frac{\sqrt{\mid x\mid-2}+\sqrt{2-\mid x \mid}}{\mid 2-x \mid}$$ and seek to find its value and the unit digit of $$M^{2003}$$.
  • One participant argues that since the square root of $$|x| - 2$$ must be zero, it leads to the conclusion that $$|x| - 2 = 0$$, resulting in potential values of $$x = 2$$ or $$x = -2$$.
  • It is noted that $$x$$ cannot be 2 due to the denominator $$|2-x|$$, leading to the conclusion that $$x = -2$$ is the only viable option.
  • Substituting $$x = -2$$ into the expression for $$M$$ yields $$M = 7$$.
  • Further calculations show that $$M^4 \equiv 1 \mod 10$$, leading to $$M^{2000} \equiv 1 \mod 10$$ and thus $$M^{2003} \equiv M^3 \mod 10$$, which is calculated as $$343 \mod 10$$, resulting in a unit digit of 3.
  • Another participant expresses appreciation for the problem and invites further mathematical contributions from others.

Areas of Agreement / Disagreement

There appears to be a consensus on the calculation of $$M$$ when $$x = -2$$, leading to the unit digit of $$M^{2003}$$ being 3. However, the discussion does not explore alternative values for $$x$$ beyond those mentioned.

Contextual Notes

The discussion assumes certain properties of the square root and absolute value functions without delving into potential edge cases or alternative interpretations of the expression for $$M$$.

anemone
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Let $$x$$ be a real number and let $$M=\frac{3x-1}{1+x}-\frac{\sqrt{\mid x\mid-2}+\sqrt{2-\mid x \mid}}{\mid 2-x \mid}$$.

Find $$M$$ and also the unit digit of $$M^{2003}$$.
 
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anemone said:
Let $$x$$ be a real number and let $$M=\frac{3x-1}{1+x}-\frac{\sqrt{\mid x\mid-2}+\sqrt{2-\mid x \mid}}{\mid 2-x \mid}$$.

Find $$M$$ and also the unit digit of $$M^{2003}$$.
Just a moment and I'll have it. I just have to program Excel...

-Dan
 
anemone said:
Let $$x$$ be a real number and let $$M=\frac{3x-1}{1+x}-\frac{\sqrt{\mid x\mid-2}+\sqrt{2-\mid x \mid}}{\mid 2-x \mid}$$.

Find $$M$$ and also the unit digit of $$M^{2003}$$.

We are taking square root of |x| - 2 and its –ve so it has to be zero
So |x| - 2 = 0 or x = 2 or – 2
x cannot be 2 as |2-x| is in denominator
so x = - 2
hence putting the value x = -2 we get M = 7
as M^4 = 1 mod 10
M^2000 = 1 mod 10 or M^2003 = M^3 mod 10 = 343 mod 10 or 3
3 is the unit digit
 
kaliprasad said:
We are taking square root of |x| - 2 and its –ve so it has to be zero
So |x| - 2 = 0 or x = 2 or – 2
x cannot be 2 as |2-x| is in denominator
so x = - 2
hence putting the value x = -2 we get M = 7
as M^4 = 1 mod 10
M^2000 = 1 mod 10 or M^2003 = M^3 mod 10 = 343 mod 10 or 3
3 is the unit digit

Hi kaliprasad,

Thanks for taking the time to participate in this challenge problem and I can tell how much you enjoyed working with some of the problems that I posted here and in case if you have any interesting mathematics problems to share with us, please feel free to do so! :o:p

topsquark said:
Just a moment and I'll have it. I just have to program Excel...

-Dan

Hi Dan,

Thank you for the reply and you know what, you're one of the clever $$\cap$$ humorous member at MHB!:cool:
 

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