Calculating Magnetic Force for 5kg Iron Sphere - Magnet Question

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To calculate the magnetic force exerted by a magnet on a 5kg iron sphere at different distances, one must consider the magnet's size and shape. The magnetic field strength typically decreases inversely with the cube of the distance, but the force on the sphere can decrease as 1/r^4 for smaller magnets. For larger magnets, the force diminishes more like 1/r^3. Therefore, the formula for calculating the force at a distance of 0.1m would differ based on the magnet's dimensions. Understanding these principles is crucial for accurate calculations in magnetic force scenarios.
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Hello, please forgive my ignorance. I need help coming up with a formula I can't seem to find on the internet. Assume I have a magnet that can attract a maximum of 5kg iron sphere against gravity from a distance .2m. My question is how much could that same magnet attract at a distance of .1m.

Wikipedia says that generally "the strength of the field falls off inversely with the cube of the distance."

Does that mean you could calculate by Mass * (Change In Distance)^3?

Please help...
 
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Your answer depends on the size and shape of the magnet and size of the iron sphere, compared to 100 cm. If it is a bar magnet of length much smaller than 10 cm and a small sphere, the magnetic field would fall off like 1/r^3, but the force on the sphere would fall off like 1/r^4. This is the force law for a dipole in the field of a dipole.
If the bar magnet is longer than ~10 cm, then force falls off more like 1/r^3.
 
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It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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