Calculating Mass and Force: A Pulley Problem

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SUMMARY

The discussion focuses on calculating the mass of a block in a pulley system, given a 100 kg block that takes 5.40 seconds to reach the floor. The acceleration was calculated using the equation sf=si + (1/2)(a)(delta t), resulting in an acceleration of 0.0686 m/s². The force acting on the 100 kg block was determined using F=ma, yielding a force of 6.86 N. Participants emphasized the importance of finding the tension in the system to solve for the mass of the block on the left.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of kinematic equations, specifically sf=si + (1/2)(a)(delta t)
  • Basic principles of pulley systems and tension
  • Ability to perform unit conversions and calculations involving mass and force
NEXT STEPS
  • Learn how to calculate tension in pulley systems
  • Study advanced kinematic equations for varying acceleration
  • Explore real-world applications of Newton's laws in mechanical systems
  • Investigate the effects of friction on pulley systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of pulley problems.

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Homework Statement



The 100 kg blcok in the figure takes 5.40 s to reach the floor after being released from rest. What is the mass of the block on the left?
knight_Figure_08_33.jpg


Homework Equations


F=ma
sf=si + (1/2)(a)(delta t)


The Attempt at a Solution



I know to find acceleration you use
sf=si + (1/2)(a)(delta t)
0=1+(1/2)(a)(5.4)
a = 0.0686 m/s2

and then the F=ma to find the force on the block of known mass.
F=(100 kg)(0.0686)
F=6.86

but from this I am not sure how to determine the mass of the block on the left?
 
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Welcome to PF!

redlightgreen said:
a = 0.0686 m/s2

and then the F=ma to find the force on the block of known mass.
F=(100 kg)(0.0686)
F=6.86

but from this I am not sure how to determine the mass of the block on the left?

Hi redlightgreen! Welcome to PF! :smile:

Find the tension, T, and then use the fact that the block on the left has the same acceleration (in the opposite direction, of course). :wink:
 
oh okay! thank you so much.
i've got it now!
 

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