Calculating Mass for a Cylinder in the First Octant

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Homework Help Overview

The problem involves calculating the mass of a surface defined by a cylinder in the first octant, where the mass per unit area is given by the function ρ=xy. The surface is constrained by another cylinder, leading to a complex integration scenario.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss parametrizing the surface and setting up the integral for mass calculation. There are attempts to determine the correct bounds for integration, with some questioning the limits of the parameter u and the impact of the cross product on the final result.

Discussion Status

Multiple participants are actively engaging with the problem, sharing their attempts and results. There is a recognition of potential mistakes in the setup and calculations, particularly regarding the bounds and the inclusion of the cross product magnitude in the integral.

Contextual Notes

Participants note discrepancies in the results obtained and express uncertainty about the correctness of their bounds and calculations. The discussion reflects a collaborative effort to clarify the setup and ensure all factors are considered in the integration process.

cp255
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If the mass per unit area of a surface is given by ρ=xy, find the mass if S is the part of the cylinder x2+z2=25 which is in the first octant and contained within the cylinder x2+y2=16.So here was my attempt.

I parametrized the curve.
x2+z2=25
r(u, v) = <5cos(u), v, 5sin(u)>

I then plugged into the bounds
x2+y2=16.
25cos2(u) + v2 = 16
v = sqrt(16 - 25cos2(u))

Next I took the cross product of ru X rv. Its magnitude is a constant 5.

Now I solved the integral with bounds 0 < u < Pi/2 and 0 < v < sqrt(16 - 25cos2(u))
∫∫25 v cos(u) du dv

This returns the result of -25/3 but since we are looking for a mass I submitted the answer of positive 25/3 and this is wrong. I checked the integration on my calculator and it gets the same result.
 
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cp255 said:
If the mass per unit area of a surface is given by ρ=xy, find the mass if S is the part of the cylinder x2+z2=25 which is in the first octant and contained within the cylinder x2+y2=16.


So here was my attempt.

I parametrized the curve.
x2+z2=25
r(u, v) = <5cos(u), v, 5sin(u)>

I then plugged into the bounds
x2+y2=16.
25cos2(u) + v2 = 16
v = sqrt(16 - 25cos2(u))

Next I took the cross product of ru X rv. Its magnitude is a constant 5.

Now I solved the integral with bounds 0 < u < Pi/2 and 0 < v < sqrt(16 - 25cos2(u))
∫∫25 v cos(u) du dv

This returns the result of -25/3 but since we are looking for a mass I submitted the answer of positive 25/3 and this is wrong. I checked the integration on my calculator and it gets the same result.

##u## doesn't go from ##0## to ##\pi/2##. Look at a picture showing what angle ##u## represents.
 
I redid my bounds and now I have arccos(sqrt(16-v^2)/5) < u < pi/2 and 0 < v < 4 which results in the answer of 22/15 which is still wrong. I fell like I found the wrong value for u.
 
I get 22/3 both that way and working the integral in reverse order so I think you have a mistake somewhere. But haven't you left out multiplying by the multiplier ##|r_u\times r_v|##? That would give 110/3 by my calculations. Is that the given answer?
 

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