- #1
galaxy_twirl
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- 1
Homework Statement
Evaluate ∫∫ F⋅dS, where F = yi+x2j+z2k and S is the portion of the plane 3x+2y+z = 6
in the first octant.
The orientation of S is given by the upward normal vector.
Homework Equations
∫∫S F⋅dS = ∫∫D F(r(u,v))⋅||ru x rv|| dA, dA=dudv
The Attempt at a Solution
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Since this is the first octant, our domain will be 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.
I have to obtain the equation of the form r(u,v) before I proceed to substitute it into the equation given by F. However, I am stuck trying to obtain the equation r(u,v).
Just wondering, is r(u,v) here the vector equation of the plane? (Cos r(u,v) is usually in the form i, j, k). From deduction, I found that x=y=z=1.
Thank you for any help given. :)