Calculating Mass of Cylinder in Rotational Dynamics Problem

AI Thread Summary
To calculate the mass of the cylinder in the rotational dynamics problem, the acceleration of the block was determined to be 0.41 m/s², with a final velocity of 0.82 m/s and a tension force of 20.42 N. The relationship between the block's acceleration and the cylinder's tangential acceleration is established, confirming they are the same due to the string's contact with the cylinder. The discussion raises a question about using the equation a = v²/r to find the cylinder's radius, clarifying that this equation pertains to centripetal acceleration rather than tangential acceleration. Overall, the calculations and concepts of acceleration are crucial for determining the mass of the cylinder. Understanding these relationships is essential for solving the problem accurately.
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A massless string is wrapped around a solid cylinder. A block of mass m=2.0 kg hangs from the string. When released, the block falls a distance 82 cm in 2.0 s. Calculate the mass of the cylinder.

Okay, for this problem, I started off with drawing free body diagrams for the block and the cylinder. I calculated the acceleration for the block to be .41 m/s^2, the final velocity of the block to be .82m/s and the force of tension of the string to be 20.42 N. Now, I think I need to calcuate the radius for the cylinder. Can I use the equation a=v^2/r to do that or is that the acceleration that is going towards the center of the cylinder?

Thanks for the help.
 
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I guess I'm assuming that the acceleration of the mass is the same acceleration as the cylinder, is that correct?
 
A point in/on the cylinder has two acceleration components - tangential and radial. The tangential acceleration of a point on the surface of the cylinder will be the same as the acceleration of the falling block since the string and the block (and therefore the outer surface of the block - the tangential acceleration) share the same linear displacement in time. since the string is in contact with the cylinder (not slipping on it) outer surface of the cylinder will travel at the same speed as the string and block at all times.
 
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