Calculating Mass of Soil Scooped in 0.009 m3

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To calculate the mass of soil that a scoop can hold, the volume of the scoop (0.009 m³) is multiplied by the density of the soil (1400 kg/m³). This results in a mass of 12.6 kg for the 0.009 m³ scoop. The discussion also explores how to calculate the mass for different volumes, emphasizing that the weight can be determined by scaling the density accordingly. The concept of a square scoop is clarified by comparing it to a box with defined dimensions. Overall, the calculation process is straightforward once the volume and density are established.
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Homework Statement



Hi,

I really need help with a problem. I have a plate and need to calculate how much soil it can dig.

Homework Equations





3. The Attempt at a Solution [/b
I first calculated the volume of the scoop (a square scoop) and after that I'm stuck. Anyone have an idea?

Volume of scoop: 0.009 m3 (I calculated this)
density of soil: 1400 kg/m3

How much soil can it hold?
 
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If the volume were 1 m3, how many kg of soil would go in ?
If it were 0.1 m3 ? 0.2 ? 0.01 ? 0.009 ?

How can a square scoop have a volume ?
 
Hey, you were my 1000 th p: ! Congrats!
 
That's true. Well, imagine a box with no top. It has a thickness, width, length and height.
From that, how am I going to calculate how much soil it can contain? Maybe should start with that

hehe, np
 
I still don't understand where you encounter a problem here: You have a volume and you have a weight per unit volume, so calculating the weight of this particular volume is straightforward. Right ?

If 1 m3 weighs 1400 kg, how much does 2 m3 weigh? And 0.5 m3 ? 0.1 m3 ? 0.2 ? 0.01 ? 0.009 ?
 

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