Calculating Mass of Triangle Surface Given Density 4xz

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To calculate the mass of the triangle surface with vertices (2,0,0), (0,2,0), and (0,0,1) given a density of 4xz, the surface area must first be determined using the formula dS = sqrt(3/2) dA. The variable density 4xz requires substituting z with its expression in terms of x and y derived from the plane equation. This substitution is crucial for integrating the density over the surface area to find the mass. Understanding how to express z in terms of x and y is key to progressing in the solution. The discussion emphasizes the importance of correctly relating the density to the surface area for accurate mass calculation.
s3a
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Homework Statement


Find the mass of the surface of the triangle with vertices (2,0,0), (0,2,0) and (0,0,1) if the density is 4xz. The solution is attached as TheSolution.jpg.

Homework Equations


Integration. Cross product. Plane equation: a(x-x_0) + b(y-y_0) + c(z-z_0) = 0 where <a,b,c> = n (vector that is normal to the plane) and where (x_0,y_0,z_0) is any arbitrarily chosen vertice.

The Attempt at a Solution


Having watched (1) and read (2),:

(1)
(2) http://www.math.oregonstate.edu/hom...usQuestStudyGuides/vcalc/surfint/surfint.html

I have successfully reached the dS = sqrt(3/2) dA step and for the next step, I'm supposed to multiply the density by the surface area in order to get the mass of the surface but, I just don't see how I'm supposed to get the (4x – 2x^2 – 2xy) part nor do I see how the variable density, 4xz, relates to that; I'm not sure that it should relate but I feel it should.

Could someone please help me understand the step I am stuck on?

Any help would be greatly appreciated!
Thanks in advance!
 

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s3a said:

Homework Statement


Find the mass of the surface of the triangle with vertices (2,0,0), (0,2,0) and (0,0,1) if the density is 4xz. The solution is attached as TheSolution.jpg.

Homework Equations


Integration. Cross product. Plane equation: a(x-x_0) + b(y-y_0) + c(z-z_0) = 0 where <a,b,c> = n (vector that is normal to the plane) and where (x_0,y_0,z_0) is any arbitrarily chosen vertice.

The Attempt at a Solution


Having watched (1) and read (2),:

(1)
(2) http://www.math.oregonstate.edu/hom...usQuestStudyGuides/vcalc/surfint/surfint.html

I have successfully reached the dS = sqrt(3/2) dA step and for the next step, I'm supposed to multiply the density by the surface area in order to get the mass of the surface but, I just don't see how I'm supposed to get the (4x – 2x^2 – 2xy) part nor do I see how the variable density, 4xz, relates to that; I'm not sure that it should relate but I feel it should.

Could someone please help me understand the step I am stuck on?

Any help would be greatly appreciated!
Thanks in advance!


You have expressed the plane as z in terms of x and y. In the integral, the z in the density formula 4xz must be replaced by its value in terms of x and y on the plane.
 
Last edited by a moderator:
Thanks!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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