Calculating Mean Square Value of a Thermoelectric Ammeter Circuit

AI Thread Summary
The discussion focuses on calculating the mean square value of a thermoelectric ammeter circuit, specifically addressing the confusion around the integration limits for periodic signals. It clarifies that the integral can be taken over any complete cycle, whether from -T/2 to T/2 or from 0 to T, as the average remains consistent. Additionally, the difference in the final answer for the mean square value compared to i^2 is acknowledged, suggesting the presence of a sine wave combined with its second harmonic. Understanding these concepts is essential for accurately interpreting the readings on the ammeter for alternating current. The importance of selecting appropriate integration limits and recognizing waveform characteristics is emphasized.
MissP.25_5
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I don't understand a few things here.

Firstly, here's the question:

This is thermoelectric ammeter. Internal resistance can be ignored.
1. Find the mean square value of the circuit.
2. Find the value that is displayed on the ammeter (alternating current).

In the textbook, the formula for the mean square value of a periodic signal is given -T/2 to T/2 as the integral region but here in the answer given, it's from 0 to T. Why?

And how come the final answer for number 1 differs from i^2?
 

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Hi MissP. It doesn't matter what the region is, so long as it covers one complete cycle of the periodic waveform. You can choose whatever end-points you like, or just whatever is convenient. The average over any duration of T will be the same, wherever you choose as the starting point. (If it isn't, then it's not a periodic wave.)

I'm guessing that you are determining the RMS value of a wave comprising a sine wave plus some of its second harmonic?
 

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