Calculating Mechanical Energy Lost to Friction on Ski Slope

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SUMMARY

The discussion focuses on calculating the mechanical energy lost to friction for a 58.1-kg skier sliding down a 122.3 m ski slope at a constant speed of 12.1 m/s, with a slope angle of 10.3°. The key equation used is Emec = KE + PE, where kinetic energy (KE) and potential energy (PE) are critical for determining energy loss. The skier's constant velocity indicates that the forces acting on them are balanced, implying that the frictional force equals the component of gravitational force acting down the slope.

PREREQUISITES
  • Understanding of mechanical energy concepts, including kinetic energy (KE) and potential energy (PE).
  • Knowledge of trigonometric functions, specifically sine, to calculate height from the slope angle.
  • Familiarity with Newton's laws of motion, particularly the concept of balanced forces.
  • Basic algebra for manipulating equations and solving for unknowns.
NEXT STEPS
  • Calculate the height of the slope using the sine function based on the given angle.
  • Determine the gravitational force acting on the skier and its components along the slope.
  • Analyze the relationship between kinetic energy and potential energy to find the energy lost to friction.
  • Explore the concept of work done against friction and its implications in real-world skiing scenarios.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain energy concepts in practical applications like skiing.

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Homework Statement



How much mechanical energy is lost to friction if a 58.1-kg skier slides down a ski slope at constant speed of 12.1 m/s? The slope is 122.3 m long and makes an angle of 10.3° with respect to the horizontal.

Homework Equations



Emec=KE+PE

The Attempt at a Solution



I first found the height of the slope by using sin. Then I tried calculating the difference in PE and KE but it was wrong. I don't know where to go from here.
 
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Since the the skier is moving with constant velocity, what does this tell us about the forces acting on the skier and how it relates to friction?
 

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