Calculating Momentum of Gun-Fired Shell

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The discussion focuses on calculating the momentum of a gun-firing shell using the conservation of momentum principle. The user is attempting to derive the equation v = v(1+m)M, where the gun has mass M and the shell has mass m, with the shell's velocity being v. The user expresses uncertainty about how to incorporate the initial conditions, specifically that the initial velocity of the system is zero, which implies that the initial momentum is also zero. They are seeking clarification on how to set up the equations correctly to reflect this conservation of momentum. The conversation emphasizes the need to balance initial and final momentum to solve the problem accurately.
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Using the conservation of momentum I need to show that a gun firing a shell will equal:

v=v(1+m)M

Where the gun of mass M shoots a shell with mass m and a velocity of v.
There are no external forces, ie the gun is free to recoil.
And its the velocity with respect to the ground...

This is what I've gotten to

v(m +M) = Mv(s) - mv(g)

v=Mv(s) - mv(g) / (m + M)
I'v done more, but I'm not if need to equal something to zero somewhere, since technically v (initial) is zero...

help?
 
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What exactly is the question asking... if the initial velocity of the system is 0, then the initial momentum of the system is 0.

So: initial momentum = final momentum

0 = Mbullet*vbullet - Mgun*vgun
 
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