Calculating Mu from a counterbalanced inclined plane

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SUMMARY

The discussion focuses on calculating the coefficient of friction (mu) from a physics lab involving a counterbalanced inclined plane with a pulley system. The students measured the mass required to maintain a nearly constant speed of a rolling cylinder at various angles. The key equation derived is mu = (T - m*g*sin(theta)) / (m*g*cos(theta)), where T represents the tension in the string. The challenge lies in determining the values for T and m, with suggestions to apply Newton's laws to find T and consider measuring m directly or using graphing techniques for further analysis.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Familiarity with inclined plane physics
  • Basic knowledge of friction and its coefficients
  • Ability to perform vector analysis in physics
NEXT STEPS
  • Apply Newton's Laws to calculate tension in the counterbalance mass
  • Measure the mass of the rolling cylinder directly
  • Explore graphing techniques to analyze motion on an inclined plane
  • Study the relationship between angle and friction in inclined planes
USEFUL FOR

Students in physics courses, educators teaching mechanics, and anyone interested in practical applications of friction and motion on inclined planes.

Sadoian
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The physics homework for the weekend dealt with a lab we did the previous day. Currently I'm stuck, and wondering if anyone can help direct me in the right direction.

The lab consisted of an inclined plane with an attached pulley. We hooked up a rolling cylinder to a string, that went over the pulley, and on the other side we added weights to balance out the system. The next step was to slowly add weight until we could get the cylinder rolling up the plane at a nearly constant (or as close as we could get it) speed, and writing down how much mass we used to get the cylinder to move at that rate.

We students did this for a variety of angles for the plane, and took down just the mass of the counterbalance each time.


Now, our assignment for the weekend was to calculate mu from the data we took from the lab. We assumed that the pulley and string were both massless and frictionless. My train of thought (up to where I became stuck)

For the cylinder:

Sigma(F-subx) = m*a-subx
Sigma(F-subx) = 0 (since a-subx is 0, assuming nearly constant velocity)

T - m*g*sin(theta) - Friction = 0
T - m*g*sin(theta) - mu*m*g*cos(theta) = 0 (taken from vertical components of FBD)

So I get mu by itself and have:

mu = (T - m*g*sin(theta)) / (m*g*cos(theta))


Now, I have T, m, and mu that I do not have values for. I can find the numerical value for T -- (the weight of the counterbalance -> m*g). Even so, I'm still stuck with m without a value, and I don't really know how I can get m to cancel out, or to find a suitable substitute to solve the equation.

Any help would be appreciated. Thank you for your time.

-Jared
 
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Sadoian said:
The physics homework for the weekend dealt with a lab we did the previous day. Currently I'm stuck, and wondering if anyone can help direct me in the right direction.

The lab consisted of an inclined plane with an attached pulley. We hooked up a rolling cylinder to a string, that went over the pulley, and on the other side we added weights to balance out the system. The next step was to slowly add weight until we could get the cylinder rolling up the plane at a nearly constant (or as close as we could get it) speed, and writing down how much mass we used to get the cylinder to move at that rate.

We students did this for a variety of angles for the plane, and took down just the mass of the counterbalance each time.


Now, our assignment for the weekend was to calculate mu from the data we took from the lab. We assumed that the pulley and string were both massless and frictionless. My train of thought (up to where I became stuck)

For the cylinder:

Sigma(F-subx) = m*a-subx
Sigma(F-subx) = 0 (since a-subx is 0, assuming nearly constant velocity)

T - m*g*sin(theta) - Friction = 0
T - m*g*sin(theta) - mu*m*g*cos(theta) = 0 (taken from vertical components of FBD)

So I get mu by itself and have:

mu = (T - m*g*sin(theta)) / (m*g*cos(theta))


Now, I have T, m, and mu that I do not have values for. I can find the numerical value for T -- (the weight of the counterbalance -> m*g). Even so, I'm still stuck with m without a value, and I don't really know how I can get m to cancel out, or to find a suitable substitute to solve the equation.

Any help would be appreciated. Thank you for your time.

-Jared

You forgot one crucial step: Do a Newton's Law problem on the counterbalance mass. That will give you a value for T. As far as m is concerned, if you are doing the problem the way you state it then you need to have measured it. The only other way involves graphing and you didn't mention that.

-Dan
 
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