Calculating Muzzle Velocity for Projectile Motion Cannon - 47 meters Fired

AI Thread Summary
To calculate the initial muzzle velocity of a cannon that fired a projectile 47 meters, the assumption of a 45-degree angle for maximum range is necessary. Without additional information about the angle or other parameters, the problem cannot be accurately solved. Using the formula for maximum range, the initial velocity can be derived as approximately 20.5 m/s. This calculation assumes that the projectile was fired at the optimal angle for distance. Providing complete details of the question is crucial for accurate problem-solving.
NIZBIT
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Someone was fired 47 meters from a cannon. What is th einital muzzle velocity of the cannon?

Am I supposed to assume max range which puts the cannon at 45deg?
 
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If that's exactly how the question was worded, that would be my guess.
 
Well I took out the fancy stuff, but all they gave was the range.
 
NIZBIT said:
Well I took out the fancy stuff, but all they gave was the range.

No angle? No mention of horizontal / vertical? Impact velocity etc?

~H
 
NIZBIT said:
Well I took out the fancy stuff, but all they gave was the range.

It's very easy to overlook useful information. So be careful. In fact, I think it's best if you post the question as it was given to you.
 
NIZBIT said:
Someone was fired 47 meters from a cannon. What is th einital muzzle velocity of the cannon?

Am I supposed to assume max range which puts the cannon at 45deg?
As Siddharth said, you should post the question exactly as it was given. Just stated the way you gave it, it is impossible to answer because there is no information about the initial angle. Sometimes useful information is given using words instead of numbers so every word counts.
 
OK you wanted it. Actually you don't need the angle and as stated earlier for max range the angle has to be 45.

In April 1959, Miss Victoria Zacchini was fired 47m from a cannon in Madison Square Garden, New York City. What was the inital muzzle velocity of the cannon?

max range=\frac {v^2}{g}

so

47=\frac {v^2}{9.81}

v=20.5 m/s
 
Of course , she was trying to set some kind of a record, and so the range would have to be maximum. See how useful posting the entire question can be ?

Arun
 
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