Calculating New Northward Speed of Air Parcel

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The discussion revolves around calculating the new northward speed of an air parcel initially moving at 10 m/s at 45°S after two hours. The Coriolis force is introduced, which affects the direction of the parcel's movement but not its speed. A participant questions the terminology used in the problem, particularly regarding the concept of "northward component" of speed, noting that speed is a scalar. Another participant clarifies that "northward speed" refers to the magnitude of the velocity in the northward direction. Ultimately, the focus is on understanding how Coriolis effects influence the air parcel's trajectory rather than its speed.
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Homework Statement



A parcel of air initially moves northward at a speed of 10 m/s at 45°S. After two hours, determine the new northward speed.

Homework Equations



Energy of a parcel= u^2+v^2

The Coriolis force accelerates a parcel such that, du/dt=fv and dv/dt=-fu
where f=2Ωsin\varphi \varphi =latitude and Ω=angular velocity of earth


The Attempt at a Solution



My first question about this problem is in regards to what it is asking for. It says to find the new northward speed of the parcel, however the Coriolis force only changes direction, not speed. So I then considered that the northward component of speed would change and that must be what the question is asking for. But then I thought about how speed is a scalar, not a vector, so there would be no "northward component" of speed because there simply aren't speed vectors. Please correct me if I'm wrong.
 
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Welcome to PF,

So you're just hung up on terminology? The "northward speed" means the speed in the northward direction, which is the magnitude of the northward component of the velocity.
 
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