Calculating Number Densities of Pu and Na in a Mixture

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The discussion centers on calculating the number densities of 239Pu and 23Na in a mixture with 5 volume percent (v/o) Pu and 95 v/o Na. Participants clarify that volume percent refers to the ratio of the volume of a substance to the total volume of the mixture, which can be expressed in consistent volume units. The need for understanding volume percent is emphasized, as it differs from atomic and weight percent calculations previously encountered in the class. The explanation includes examples to illustrate how volume percent works in practical scenarios. Ultimately, mastering this concept is essential for accurately determining the number densities of the elements in the mixture.
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Homework Statement


1. Consider a mixture consisting of 5 v/o 239Pu and 95 v/o 23Na. Using the g′ = 1, . . .


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The Attempt at a Solution


Is v/o volume percent? I have never ran across this notation before and am not too sure how to handle it. I tried googling it but the results are not helpfull. Ultimately I need to calculate the number densities of Pu and Na, and we have only used atomic and weight percents in this class.

http://en.wikipedia.org/wiki/Volume_percent
Thanks.
 
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Volume percent is the ratio of the volume of a substance to the total volume of a mixture. The volume percentage of water in a glass of ice and water is 50% and the volume percentage of salt in a salt water solution is 15%. You can use any unit of volume as long as it is the same for both the part and the whole. For example, you can use milliliters and liters as long as they are all the same. Volume percent is a way of working out the amount of a substance in a mixture, as it is a proportion.
 
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