Calculating Oxygen Gas Released from Heating Calcium Chlorate

[Mackydoodle]

Homework Statement

How many millilitres of oxygen gas are released from heating 5.00 grams of calcium chlorate?

Homework Equations

Ca(ClO3)2→CaCl2+3O2

Ca(ClO3)2 =207.7g
CaCl2=110.98g
O2=22.4 g/L
Mole ratio= 3mol O2/1mol Ca(Clo3)2

The Attempt at a Solution

This is what I have but it is not coming out right and I just can't figure out where I am going wrong. I am having trouble with these kinds of problems.

(207.7 g/ 1 mol Ca(Clo3)2) X (1mol Ca(Clo3)2/3 mol O2) X (22.4 L O2/ 1 mol O2)= 1550.8
(this can't be right the answer is supposed to be 1620)

 

[AGNuke]

Moles of Calcium Chlorate (Given Mass / Molar Mass)* Moles of dioxygen per mole of Calcium Chlorate (3) * Volume of 1 mole dioxygen (22.4 L / mol).

The answer is approximately 1617. (1620 if you approximately calculate it manually)

 

[Mackydoodle]

I now see where I went wrong! thank you :)