Calculating P(2013) of Polynomial P(x) of Degree 2012

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To find P(2013) for the polynomial P(x) of degree 2012, where P(k) = 2^k for k = 0, 1, ..., 2012, the discussion suggests examining simpler polynomial cases to identify a pattern. By analyzing polynomials of degrees 2 and 3 with specific values, participants are encouraged to derive coefficients and predict values for subsequent inputs. The goal is to establish a consistent pattern that can be generalized to higher degrees. This method emphasizes the importance of recognizing relationships between polynomial degrees and their outputs. Ultimately, the discussion aims to confirm the pattern holds true for P(2013).
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P(x) is polynomial of degree 2012, P(k)=2^k, k=0,1,...,2012. Find P(2013)
 
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Start by looking at simpler versions:

Suppose P is polynomial of degree 2, P(0)= 1, P(1)= 2, P(2)= 4. Since P is of degree 2 we can write it as P(x)= ax^2+ bx+ c. Use P(0)= 1, P(1)= 2, P(2)= 4 to find a, b, and c. What is P(3)?

Suppose P(x) is a polynomial of degree 3, P(0)= 1, P(1)= 2, P(2)= 4, P(3)= 8. Since P is of degree 3, P(x)= ax^3+ bx^3+ cx+ d use the values at x= 0, 1, 2, and 3 to find a, b, c, and d. What is P(4)?

Do you see a pattern? Can you show that this pattern is correct?
 
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