Calculating pH of a solution with two weak acids and a strong base

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To calculate the pH of a solution containing two weak acids (acetic acid and hydrogen sulfide) and a strong base (sodium hydroxide), one must consider the neutralization reactions and the remaining concentrations of the acids after partial neutralization. The strongest acid, acetic acid, will be neutralized first, followed by hydrogen sulfide. The Henderson-Hasselbalch equation can be applied to determine the pH after accounting for the amounts of each acid that remain unneutralized. It is essential to calculate the extent of neutralization for each acid based on their dissociation constants (Ka values). Ultimately, the solution's pH can be derived from the remaining concentrations of the weak acids and their respective dissociation equilibria.
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Homework Statement


0.5332 M CH3COOH
0.1219 M CH3COONa
0.100 M H2S

0.41452 M NaOH

what is the pH of the resulting solution?

Homework Equations



CH3COOH Ka=1.75E-5
H2S Ka1=9.6E-8, Ka2=1.3e-14

The Attempt at a Solution



I know that neutralisation will occur, but there is not enough strong base to neutralize all of the weak acids. How do you know how much of each acid the base will neutralize? How would you calculate pH then? I know if there was one weak acid you could use the Hendelson-Hasselbach equation but I don't know what do with two weak acids :(
 
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Strongest acids are neutralized first.

Idea of using Henderson-Hasselbalch equation is a right one, just start with the first hint and see what you get after using all base.
 
yup
borek has provided u with almost all of the reqd. hints!:-p
 
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