Calculating Phase Angle & Voltage in Series RL Circuit

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In a series RL circuit with a resistor of 1Ω and an inductor with a reactance of 1Ω, the total impedance can be calculated using the formula Z = √(R² + X_L²), resulting in an impedance of √2Ω. The phase angle (φ) between the current and supply voltage is determined using φ = arctan(X_L/R), which yields a phase angle of 45 degrees. The voltage across the resistor (V_R) is calculated using Ohm's Law (V = IR), resulting in a voltage of 1V. The voltage across the inductor (V_L) can be found using V_L = I * X_L, giving a voltage of 1V as well. Thus, both the resistor and inductor develop equal voltages of 1V, with a phase angle of 45 degrees.
Solidsam
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An inductor “L” is connected in series with a Resistor “R”. This circuit is connected to
a sinusoidal voltage “V”, and a current of 1A flows. If the circuit resistor has a value
of 1W, and the magnitude of the reactance of the inductor “L” is 1W at the supply
frequency, state:

(i) The phase angle of the current with respect to the supply voltage

(ii) The magnitude of the voltage developed across the Resistor “R”, and the
inductor “L”



Like where do I even start? what equations should I be looking at?
 
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Hi Solidsam! :wink:

Start by finding the impedance :smile:
 

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