Calculating Potential Energy in a Rotary Mousetrap Spring System

AI Thread Summary
The discussion focuses on calculating the potential energy of a spring in a rotary mousetrap system as a function of the angle the spring is pulled back. The initial approach suggests using the relationship x = rΘ and integrating to find potential energy, resulting in PE = ½k(rΘ)^2. However, participants clarify that mousetraps typically use torsion springs, leading to the correct formula for potential energy as PE = ½kθ^2, where k is the spring constant. Questions about the linearity of the spring and potential measurements to determine k are raised, emphasizing the need for experimental validation. Overall, the conversation highlights the importance of understanding the type of spring and its behavior in calculating potential energy.
JLT
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Homework Statement



Calculate the potential energy created by the spring in the mousetrap as a function of the angle the spring is pulled back.

Homework Equations



PE = ∫Fdx = ∫ kxdx = ∫k rΘ rdΘ ??

The Attempt at a Solution



Is this a linear spring? we can use x = rΘ, and dx = rdΘ, so PE = ½k(rΘ)^2

↑↑ does that look good to everyone, or is there a better soln to this?
 
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Is this an experiment? What measurements could you take to help determine if it is linear and to determine k?
 
JLT said:
the spring in the mousetrap
Is there a diagram with this?
It sounds like a so-called torsion spring. Mousetraps generally use those.
 
OK, although for a rotary system the spring constant is usually given as τ = kθ, τ = torque, then
p.e. = 1/2 kθ2.
 
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