Calculating Power Needed for a Machine's Flight: Tips & Tricks

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To calculate the power needed for a machine's flight, it's crucial to understand that the machine's engine output remains at 60 watts despite energy losses due to air resistance. In this case, the machine loses 2.5 * 10^3 Joules to air resistance while gaining potential energy as it ascends to 2230 meters. The total power supplied by the engine accounts for both the energy lost and the energy gained. Therefore, the effective power used for flight remains 60 watts. Understanding these energy dynamics is essential for accurate calculations in flight mechanics.
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For example, if it takes 60 watts of Power for a machine to fly, yet loses (for instance) 2.5 * 10^3 Joules of its energy because of the air resistance, what's the amount of "Power" that was really given in the first place?

The time of flight for the machine is 30 minutes to get to the height of 2230 meters.

Any suggestions or tips? I've been stumped by this problem for a while now.

Thanks.
 
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It seems that the power is still going to be 60 watts -- even though energy is being lost to air resistance, the engine of the machine is still going to be putting out that much power. So when it flies to a height of 2230 meters, it loses 2.5 * 103 J to air resistance, while also gaining potential energy. Both of these energies will be supplied by the power source.
 
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