Calculating power over a frequency band

AI Thread Summary
To measure total power over a bandwidth using a Spectrum Analyzer, one can take readings in dBm without converting to watts. The noise power is calculated using the formula kTB, resulting in approximately -111 dBm per MHz after accounting for the noise figure. The user inquired about integrating power readings across a specified frequency range, with example dBm values provided. Understanding the frequency resolution of the analyzer is crucial, as it impacts the energy readings within the measurement window. Properly setting the Resolution Bandwidth (RBW) and Video Bandwidth (VBW) can help achieve a lower noise floor for more accurate measurements.
newenglandguy
Messages
3
Reaction score
0
I am interested in taking a measurement with a Spectrum Analyzer from an amplifier circuit I'm putting together and am interested in calculating the total power over a certain bandwidth. Is is just a matter of taking all the readings in dBm, converting to watts and then taking the RMS values taken from the Spectrum Analyzer across my band of interest? The only power into the amplifier will be the noise power. The amplifier has 45 dB gain.

I understand some Spectrum Analyzers have an option that allows you to measure this directly, but the Spectrum Analyzer I have access to does not have this functio

Thanks
 
Physics news on Phys.org
I will guess that the noise power is about -111 dBm per MHz**., including 3 dB noise figure, and 45 dB gain to get -66 dBm per MHz. You don't need to convert to watts. Just use dBm.

Bob S

** the noise power is kTB where k= 1.38 x 10-20 millijoules per deg kelvin, T=293 kelvin, and B(bandwidth in Hz)= 1 MHz

So noise power is 1.38 x 10-20 x 293 x 106 = 4 x 10-12milliwatts per MHz = -114 dBm per MHz.

Add 3 dB noise figure to get -111 dBm per MHz
 
Bob - thanks for the reply. That's noise power, but once I hook up the amplifier, I'll get some trace that represents the output noise power versus frequency. How do I calculate total power over that bandwidth? Say I have the following readings versus F1 - F2:

-55.6 dBm, -55.7 dBm, -56.2 dBm, -57.2dBm, -57.8 dBm, -56.9 dBm.

I guess thr question I have is how I integrate (think that's the right term) power over that bandwidth?

Thanks
 
Do you know the frequency resolution of the analyzer? Presumably, values of -55.6 dBm (i.e. 2.75 nW), etc. correspond to the energy contained within the window around the frequency to which the analyzer is tuned. The size of the window is either adjustable or can be found in the manual.
 
hamster143 - I want to get the Noise Floor of the Spectrum Analyzer down to -65 dBm or lower, and I planned on setting the Resolution Bandwidth (RBW) and the Video Bandwidth (VBW) to 30 KHz.
 
newenglandguy said:
hamster143 - I want to get the Noise Floor of the Spectrum Analyzer down to -65 dBm or lower, and I planned on setting the Resolution Bandwidth (RBW) and the Video Bandwidth (VBW) to 30 KHz.
If you back-terminate the input to the spectrum analyzer with a good matched resistor, the noise level should be in the range -114 to -111 dBm per MHz bandwidth (not per MHz resolution). See my post #2.

Bob S
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top