Calculating Pressure Change in Liquid After Adding Weight

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    Liquid Pressure
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The discussion centers on how adding a weight, specifically an aluminum ball, affects the pressure at the bottom of a cup filled with water. When the ball is placed in the cup, even though it is held by a string and does not sink, the water level rises, which increases the depth of the water. According to the liquid pressure equation p = ρgh, the pressure at the bottom of the cup increases due to the greater height of the water column. The initial understanding that the pressure increases with the water level is confirmed. Therefore, the pressure at the bottom of the cup does indeed change as a result of the added weight, even if the ball does not sink.
mr.book
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This started to bother me today. In the first picture, there's a cup wheres a certain amount of water in it. A ball made of aluminium hasnt been dropped in the cup yet.
In the second picture, the ball has been dropped in.

The ball has not sinked, a string is holding it.

Now please tell me, how did the pressure on the botton of the cup created BY THE WATER change?
I mean, the water level just rose. So the pressure should also.
But there seems to be another solution to the problem, and I just can't figure it out.

The equation for liquid pressure is p= RO*g*h.

Thanks in advance,






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Your initial solution is correct. Since the depth of the water is now larger, the pressure at the bottom is higher.
 

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