- #1
Muck
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The question: A baseball player has a 5% chance to hit a homerun each at bat. If the player is up 4 times, what is the chance he hits 2 or more homeruns. I came up with the answer, but this was a long process. I need a formula. And is there an easier way of counting the possibilities?
I did it like this:
Probability of 0 out of 4 + 1 out of 4 = 1.401875
Probability of 0 out of 4 is (0.95)(0.95)(0.95)(0.95)(1) with 1 possibility
Probability of 1 out of 4 is (0.05)(0.95)(0.95)(0.95)(4) with 4 possibilities so
The other 11 possibly scenarios are 6 to do 2 out of 4, 4 to do 3 out of 4, and 1 to do 1 out of 4, for a total of 16 (4x4) but is there an easier way than counting these?
Thank you!
EDIT: for 'player' :)
I did it like this:
Probability of 0 out of 4 + 1 out of 4 = 1.401875
Probability of 0 out of 4 is (0.95)(0.95)(0.95)(0.95)(1) with 1 possibility
Probability of 1 out of 4 is (0.05)(0.95)(0.95)(0.95)(4) with 4 possibilities so
The other 11 possibly scenarios are 6 to do 2 out of 4, 4 to do 3 out of 4, and 1 to do 1 out of 4, for a total of 16 (4x4) but is there an easier way than counting these?
Thank you!
EDIT: for 'player' :)
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