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Calculating probability of an event

  • Thread starter Nyasha
  • Start date
  • #1
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Homework Statement


Find the probability of the following statement :

[tex]P(A\prime \cap C | B \prime )[/tex]



2. The attempt at a solution

[tex]P(A \prime \cap C | B\prime ) =\frac{P ( A \prime \cap C \cap B \prime)}{P(B \prime)}= \frac{P ( A \prime \cap C \cap B \prime)}{1-P(b)}[/tex]

I am stuck as to how do l deal with the numerator. Can someone please help me ?
 

Answers and Replies

  • #2
lanedance
Homework Helper
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what are you trying to do?
 
  • #3
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what are you trying to do?
I am trying to calculate the probability of [tex]
P(A\prime \cap C | B \prime )
[/tex]. More of like trying to find the algebraic expression to calculate the probability of [tex]
P(A\prime \cap C | B \prime )
[/tex].
 
Last edited:
  • #4
lanedance
Homework Helper
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2
in terms of what? ie what form are you trying to simplify to/express in?
 
  • #5
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in terms of what? ie what form are you trying to simplify to/express in?
I am trying to make it as simple as possible so that if given the values of A,B&C you can calculate the probability
 
  • #6
lanedance
Homework Helper
3,304
2
sorry, its still not clear exactly what you;re trying to do, is this an actual question? given what values?

you will need P(A), P(B), P(C) and some info about their intersections/unions

you could use some basic set theory to re-arrange, but it all depends want you want it in terms of, for example, deriving quickly from venn diagrams

looking at 2 sets A & B
[tex] P(A) + P(B) = P(A \cup B) + P(A \cap B) [/tex]

then adding another set C
[tex] P(A) + P(B) + P(C) = P(A \cup B \cup C) + P(A \cap B) + P(B \cap C) + P(C \cap A) -P(A \cap B \capC) [/tex]
 
Last edited:

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