Calculating Probability with Normal Approximation

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Homework Help Overview

The discussion revolves around a statistics problem involving the calculation of probability using the normal approximation to the binomial distribution. The specific scenario presented involves determining the probability of observing a certain number of drivers wearing seat belts in a sample of 700 drivers, given that 80% of drivers wear seat belts.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the mean and variance of the normal approximation, with one participant providing a detailed calculation of the exact probability. Others express confusion about the calculation and request clarification on the steps taken.

Discussion Status

The conversation is ongoing, with some participants seeking further explanation of the calculations involved. There is an emphasis on understanding the problem rather than simply obtaining a solution, as one participant notes the importance of sharing their own thoughts and work to facilitate assistance.

Contextual Notes

Participants are reminded of the forum's policy against providing complete solutions, which may influence the nature of the responses and the level of detail shared in the discussion.

lilyungn
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Hi all I'm currently taking Statistics 1 and I'm stuck on a homework problem that I've been trying to figure out for a while...hopefully one of you guys can enlighten me on how to do it..heres the question:

Transportation officials tell us that 80% of drivers wear seat belts while driving. What is the probability of observing 518 or fewer drivers wearing seat belts in a sample of 700 drivers?

Hint: Use normal distribution to approximate the binomial distribution

Any help will be greatly appreciated. Thanks
 
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The normal approximation of the binomial distribution has mean n * p and variance n * p * (1 - p). In your example n = 700 and p = 0.8.

I calculate the exact probability as
Code:
27215033424606239489951580591428932253089201021148168958765691731392094513257400149512461174994101101893879349950817724535023320833098115143452605318902844562357900521627169600482502350655645510044817056094897193166242140544070444191441905644096259918364809861980951251235754139967622866482769375805893409967413796426281723416461645206238828172038546224013601381995986790697562819660604903531492876045502982090073701576428830644538188684724158694295977900811634082990023633233789421341/380218313259031964703014481167020621852974241274703806488349211513170849855494440711440299410524372640522125900659637734955652488757724700708924916770505595637569416206346918582471539076959056068435223651008041554876432039792771230305103084765331596853800084507271724280140484161410403670670196458543283896996507022028449859411384981297711080778428012558385332383706122652531298594333598103700679951981973698960512606011735240635218234741615222116624395187756135783274658024311065673828125
You can use this to check yourself, if you'd like. :-p
 
I don't understand how you did it, can you show the work? thanks
 
lilyungn said:
I don't understand how you did it, can you show the work? thanks
No, we cannot; that is cheating, strictly against site policy, and not very effective in helping you learn anyways.

What we will do is help you solve the problem, but we can't do that if you only post the question, and nothing about your own thoughts, work, and understanding about it.
 
CRGreathouse said:
The normal approximation of the binomial distribution has mean n * p and variance n * p * (1 - p). In your example n = 700 and p = 0.8.

I calculate the exact probability as
Code:
27215033424606239489951580591428932253089201021148168958765691731392094513257400149512461174994101101893879349950817724535023320833098115143452605318902844562357900521627169600482502350655645510044817056094897193166242140544070444191441905644096259918364809861980951251235754139967622866482769375805893409967413796426281723416461645206238828172038546224013601381995986790697562819660604903531492876045502982090073701576428830644538188684724158694295977900811634082990023633233789421341/380218313259031964703014481167020621852974241274703806488349211513170849855494440711440299410524372640522125900659637734955652488757724700708924916770505595637569416206346918582471539076959056068435223651008041554876432039792771230305103084765331596853800084507271724280140484161410403670670196458543283896996507022028449859411384981297711080778428012558385332383706122652531298594333598103700679951981973698960512606011735240635218234741615222116624395187756135783274658024311065673828125
You can use this to check yourself, if you'd like. :-p

Seems a little large for a probability, being that they should be in the interval [0, 1].
 

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