Calculating Projectile Motion: Distance of Cannonball to Black Pearl

AI Thread Summary
To calculate the distance from the cliff to the Black Pearl, the projectile motion of the cannonball must be analyzed. The cannonball is fired at an initial speed of 50 m/s at an angle of 30°, with the cliff height being 100 m. The vertical displacement (Delta y) is -100 m, indicating the cannonball falls from the cliff to the ship. The horizontal (Vx) and vertical (Vy) components of the velocity are determined using trigonometric functions. By applying these calculations, the horizontal distance to the Black Pearl can be accurately found.
SherazSiddiqu
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Captain Jack Sparrow shoots a cannonball at the black pearl which is located off the cliff that is 100m high. The cannon ball leaves the cannon at 50m/s at 30° to the horizon and hits the Black Pear(the ship) directly.
How far is the Black Pearl(the ship) from the cliff?

Please help thanks.
 
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Here's a picture:
35bvxab.png


So from that you can use this equation to solve:
l_vertical_displacement_equation.png

Delta y is the change in the y which is y2-y1 meaning the change in y will be -100 (NEGATIVE)Edit: I forgot you need to find the x and y components:
v cos (theta) = Vx
V sin (theta) = Vy - You need this 1, other is just for extra practice or w/e. (for this problem)
 
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