Calculating Resistance and Impedance in an Electric Circuit

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SUMMARY

The discussion focuses on calculating resistance and impedance in an electric circuit using the formulas H = (NI)/(2πr) and V = IR. The user attempted to determine the total resistance as 100 ohms, leading to a calculated current of 0.12A and a voltage across a 1-ohm resistor of 0.12V. The total impedance was estimated at 104.40 ohms with a phase angle (φ) of 15.63 degrees when the switch is open. The calculations and methodologies presented are foundational for understanding circuit behavior.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Familiarity with impedance concepts in AC circuits
  • Knowledge of basic circuit components (resistors, switches)
  • Proficiency in using trigonometric functions for phase angle calculations
NEXT STEPS
  • Study the concept of impedance in AC circuits
  • Learn about series and parallel resistor configurations
  • Explore the use of phasors in circuit analysis
  • Investigate the effects of frequency on impedance
USEFUL FOR

Electrical engineering students, hobbyists working on circuit design, and anyone interested in understanding the principles of resistance and impedance in electric circuits.

dietwater
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Homework Statement


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physics.jpg



Homework Equations



H= (NI)/ (2(Pi)r)
V=IR

The Attempt at a Solution



a)

total resitance = 100ohms?
from this would the current be 0.12A

over 1ohm resistor: 0.12V

not sure if this is correct even. Any help would be much appreciated.
 

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If I have calculated correctly, the total impedance is 104.40 ohms, \phi = 15.63^{o} when the switch is open. Then you can use V = V_{source}\frac{Z_{R}}{Z_{total}}
I'm not 100% that this is the way to do it though.
 
Last edited:

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