How to Simplify a Frequency Response Circuit for Impedance Calculation?

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Discussion Overview

The discussion revolves around simplifying a frequency response circuit for the purpose of calculating impedance. Participants explore the implications of source transformations and the role of resistors in the circuit.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether a series resistor can be ignored when simplifying a circuit with a current source and another resistor in parallel.
  • Another participant asserts that a series resistor does not affect the current delivered by the current source, suggesting it can be removed from consideration.
  • A later reply humorously emphasizes the removal of the series resistor, reinforcing the previous point about its irrelevance.
  • One participant seeks clarification on the placement of a second resistor in relation to an L-C network, indicating potential confusion about circuit configuration.

Areas of Agreement / Disagreement

There appears to be agreement among some participants regarding the removal of the series resistor, while the placement of another resistor in the circuit remains unclear and unresolved.

Contextual Notes

The discussion includes assumptions about the behavior of current sources and resistors that may depend on specific circuit configurations. The implications of source transformations are also not fully explored.

Marcin H
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Homework Statement


Screen Shot 2016-10-11 at 7.57.38 PM.png


Homework Equations


V=IR
H(w) = Y/F = Impedance of circuit

The Attempt at a Solution



I wanted to simplify this circuit before I find any impedance, but I am not sure if I did my source transformation correctly. Can i combine the f(t) current source with the 1ohm in parallel even though there is another resistor in series with it? Or are my steps correct?

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A resistor (or any passive component) in series with a current source has no effect outside of altering the potential differences on components within the current source branch. The branch will still deliver the current source's specified current with or without series resistance in the way; the current source will just alter its own potential difference to compensate and maintain the current.

What this means is that you can remove that series resistor entirely without making any change to the way the rest of the circuit operates.
 
gneill said:
What this means is that you can remove that series resistor entirely without making any change to the way the rest of the circuit operates.

So do I just ignore that resistor from the start or do I have to include it like I did in my source transformation?
 
Marcin H said:
So do I just ignore that resistor from the start or do I have to include it like I did in my source transformation?
Remove it. Erase it. Obliterate it. Pretend it never exited :smile::biggrin:
 
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gneill said:
Remove it. Erase it. Obliterate it. Pretend it never exited :smile::biggrin:
Lol.. Thanks! :smile:
 
How did your second 1 ohm reisstor wind up in series with the L-C network?
 

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