Calculating Shade Projection for Beach Sun Shade - Math Homework Solution

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The discussion centers on calculating the ground projection area of a sun shade that is 1.5 m tall, 2 m wide, and positioned at a 60° angle with the ground. Participants clarify that the angle refers to the part of the shade touching the ground, and a diagram is suggested for better understanding. The projection formula is mentioned as essential for solving the problem, but some participants express confusion about the application. The conversation emphasizes collaborative problem-solving, inviting others to share their methods or attempts. Overall, the thread aims to clarify the mathematical approach to determining the shade's ground area.
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Homework Statement


Two math students erect a sun shade on the beach. The shade is 1.5 m tall, 2 m wide, and makes an angle of 60° with the ground. What is the area of shade that the students have to sit in at 12 noon (that is, what is the projection of the shade onto the ground)? (Assume the sun’s rays are shining directly down).


Homework Equations


I've attached the formula


The Attempt at a Solution


I tried drawing a diagram with 2m at the bottom and the height being 1.5. I know I'm supposed to use the projection formula. After that I'm lost.
 

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Just for my own clarity, does it make a 60° angle with the bit that goes in the ground or with the actual shade itself? Could you produce a diagram if this seems to be a silly question?

The Bob
 
With the piece that goes in the ground. The problem didn't come with a diagram because so you have to come up with your own.
 
60 degrees is an angle in an equilateral triangle. The edge of the shadow, with the sunlight coming straight down is at the perpendicular from the vertex. This is very close to being a trivial problem!
 
how would u solve this problem guys?
 
hossai said:
how would u solve this problem guys?

Hi hossai. Welcome to PF!

The idea of these threads is to help each other solve problems they have. So, if you'd like to venutre an attempt at the solution or method for solving this then we could discuss it further.

The Bob
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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