Calculating Speed and Force of a 10m Dive

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To calculate the speed of a 65 kg diver entering the water from a 10 m platform, use the kinematic equation v_f² = v_i² + 2ad, with gravity as a negative acceleration. The final speed upon entering the water can be determined by solving for v_f. For the second part, to find the net force exerted by the water as the diver stops 2.0 m below the surface, apply the work-energy principle, equating the work done by gravity to the work done by the water. Ensure to maintain consistent sign conventions throughout the calculations.
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Can you please help me out with this problem?!?

A 65 kg person dives into the water from the 10 m platform.

a)What is her speed as she enters the water?

b)She comes to a stop 2.0 m below the surface of the water. What net force did the water exert on the swimmer?
 
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Part A is simple kinematics.
recall Vf(sq)=Vi(sq)+2(a)(d)
(carefull--a=g which is negative.)

Part B is not realistic, but can be solved easily with an energy approach. Remember that gravity does a total work of (mg)(distance). Don't forget about the distance into the water--that matters. If the diver stops, the work by gravity is the same as the work by the water= (Fwater)(distance)
 
tennisacerg said:
Can you please help me out with this problem?!?

A 65 kg person dives into the water from the 10 m platform.

a)What is her speed as she enters the water?

b)She comes to a stop 2.0 m below the surface of the water. What net force did the water exert on the swimmer?

As was already stated:

v_{f}^{2}=v_{i}^{2}+2ad

You can solve for final velocity from this.

Using the same equation, you can determine part b. You will, of course, be required to manipulate the equation to solve for a, and then multiply this result by the diver's mass to determine the force applied by the water.

Watch your signs throughout! (I.e. make positive either up or down, and then stick with that throughout.)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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