Solve Work-Energy Problem for Girl Cliff Diving

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SUMMARY

The discussion focuses on solving a work-energy problem involving a girl cliff diving from an 80-meter high cliff. Given her mass of 64 kg and a maximum withstandable force of 11,000 N, the minimum depth required to avoid injury is calculated to be 4.65 meters. Additionally, if she dives 3.8 meters underwater, the force experienced by her body is determined to be 13,473 N. It is noted that the assumption of constant force in water is not realistic.

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  • Understanding of work-energy principles in physics
  • Familiarity with the equation mgh + Fd cos(theta) = 1/2 mv²
  • Basic knowledge of forces and their effects on the human body
  • Ability to perform calculations involving mass, force, and depth
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  • Explore advanced applications of the work-energy theorem
  • Learn about the physics of diving and water resistance
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Physics students, educators, and safety professionals interested in the dynamics of diving and the application of work-energy principles in real-world scenarios.

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Homework Statement


A girl is cliff diving. She jumps (assume from rest) from an 80 meter high cliff.

a) If her mass is 64 kg, and her body can only withstand a force of 11,000 N without breaking a bone, what is the minimum depth she must go into the water and not get hurt?

b) If we assume she goes 3.8 meters under the water, what force does her body feel?

Homework Equations


mgh+Fdcos(theta)=1/2mv2f

m = 64kg, vf = 0m/s F1 = 11000N, h = 80m, d2 = 3.8m, d1 = ?, F2 = ?

The Attempt at a Solution


a) I used the above equation to solve for d2 and I got an answer of 4.65m as the depth.

b) I used the above equation to solve for F2 and I got an answer of 13,473N as the force.
 
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That all looks right. But note the question assumes the force is constant in the water. That would not be true in practice.
 

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