Calculating Speed to Reach 1.11 fm from Oxygen Nucleus

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Homework Help Overview

The problem involves calculating the speed at which a proton must be fired toward an oxygen nucleus to achieve a specific turning point distance from its surface. The context is rooted in nuclear physics, specifically dealing with potential and kinetic energy equations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of kinetic and potential energy equations, questioning the correctness of the formulas used. There are attempts to clarify the relationship between the charges involved and the setup of the problem.

Discussion Status

Multiple interpretations of the equations and their components are being explored. Some participants provide corrections to the original equations, while others express uncertainty about the calculations and the values used. There is a mix of attempts to recalculate and verify the results.

Contextual Notes

Participants note potential issues with the mass of the proton versus the electron and the correct interpretation of the radius in the context of the problem. There is an emphasis on ensuring all constants and values are accurately represented in the calculations.

Tina20
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Homework Statement



The oxygen nucleus 16O has a radius of 2.91 fm. With what speed must a proton be fired toward an oxygen nucleus to have a turning point 1.11 fm from the surface?

Homework Equations



Kinetic energy = 1/2 mv^2
Potential energy = 1/4(pi)Enot * q/radius min

The Attempt at a Solution



I combined the two above equations as follows:

1/4(pi)Enot * q/radius min = 1/2 mv^2
9x10^9 (1.602x10^-19)/(1.11x10^-15 m) = 1/2 (9.109x10^-31)v^2
1.688x10^18 m/s = v

The above answer was incorrect. I have roughly 31 hours to solve this question until it is due. Can someone please tell me if the equations I am using are wrong and which equations I should be looking at?
 
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Potential energy = 1/4(pi)Enot * q/radius min
Can't be right - you need the charge on the proton multiplied by the charge on the nucleus. The 1/4(pi) doesn't look right either - you must mean 1/(4*pi*Enot).
 


Sorry for not including the brackets, I did mean 1/(4*pi*Enot).

So I changed the way I approached this question...below is my revised attempt which still ended up being wrong:


1/(4(pi)Enot) * (q oxygen * q proton)/radius min = 1/2 mv^2
9x10^9 (8*1.602x10^-19 * 1.602x10^-19)/(2.91x10^-15m +1.11x10^-15m)=1/2 (9.109x10^-31)v^2
9x10^9 ((8*1.602x10^-19 * 1.602x10^-19)/4.02x10^-15) = 1/2 (9.109x10^-31)v^2
4.5965x10^-13 = 1/2mv^2
1.00923x10^18 = v^2
1,004,605,104 m/s = v

This answer is incorrect. I decided to add the radius of the oxygen nucleus with the turning point radius as the radius between the two point charges. Maybe my radius should be something else but the way I did it seems right to me...unfortunately it isn't right :(
 


1/2 (9.109x10^-31)v^2
Looks like you used the mass of an electron rather than the mass of a proton.
 


I recalculated by answer and used the protons mass this time. I had a final answer of 2344825.312 m/s which is still wrong. I don't know why the answer is not correct.

Everything else that has been inputted into the equations seems logical, I still must be missing something.
 


Ok, all is fine :)

I double checked everything, I must have missed a digit in one of my numbers the first time!

Final answer is 23448253.12 m/s and it is correct! Thank you for all your help Delphi51!
 


Great; most welcome!
 

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