Calculating Tension in a Hanging Mass: 15 and 25 Degree Angles

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To calculate the tension in a clothesline supporting a 12kg mass at angles of 15 and 25 degrees, the equations T1sin(15) + T2sin(25) = 117.6N and T1cos(15) = T2cos(25) are established. A participant points out a correction in the second equation, noting it should be T2cos(25) instead. With this adjustment, the problem reduces to solving two equations with two unknowns. By substituting the sine and cosine values, the tensions T1 and T2 can be determined through algebraic methods. Properly applying these steps will yield the required tension values.
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this is probably really easy but i can't get it

a 12kg mass is hanging from a clothes line. the line on the left forms an angle of 15 degrees and the angle of the line on the right forms a 25 degree angle. i have to solve for the tension on both sides of the clothesline

i drew a free body diagram and two diagrams showing the components of tension but i still can't solve it this is what i came up with so far

T1sin15 + T2Sin25 = 117.6N

T1cos15 = T2cos15
 
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cashslash89 said:
this is probably really easy but i can't get it

a 12kg mass is hanging from a clothes line. the line on the left forms an angle of 15 degrees and the angle of the line on the right forms a 25 degree angle. i have to solve for the tension on both sides of the clothesline

i drew a free body diagram and two diagrams showing the components of tension but i still can't solve it this is what i came up with so far

T1sin15 + T2Sin25 = 117.6N

T1cos15 = T2cos15
Yes, that looks almost right, but you meant T2cos25 in that last equation, I think. Now it's just algebra...plug in the numeric sin and cos values, and you have 2 equations and 2 unknowns, you should be able to solve for T1 and T2 using the algebraic method of your choice.
 
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