Calculating Tension in an Elevator Cable - Is My Solution Correct?

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The discussion revolves around calculating the tension in an elevator cable supporting a cabin with a total mass of 747 kg, which includes the mass of the cabin and passengers. The user applied Newton's second law, stating that the net force equals mass times acceleration, to derive the tension. They calculated the tension as 11,810.07 N, factoring in both the upward acceleration of 6 m/s² and the gravitational force. Other participants confirm that the calculations appear correct. The solution aligns with the principles of physics governing forces in an accelerating system.
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Homework Statement



Here is the statement :
An elevator cabin of mass 567 kg combine a mass of people inside the cabin of 180 kg.The cabin is pulled upward by a cable with a constant acceleratuon of 6 m/s².
What is the tension T of the cable

Homework Equations



I used the second law of Newton :
Fnet = ma
with m = 567 + 180 = 747

The Attempt at a Solution



so T+ Fg = ma
and T= ma+ mg
so T= 11810.07 N

IS IT CORRECT ??
 
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Looks OK.
 

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