Calculating Tension in an Inclined Plane Problem

AI Thread Summary
To determine the tension in the rope pulling a 1200-N go-cart up a 25-degree incline at a constant speed, the forces acting on the cart must be analyzed. Initially, the force required to pull the cart parallel to the horizontal was calculated as 507.14 N using the sine function. However, when considering the angle of the rope, the calculation was adjusted, leading to a tension value of 618.46 N. The correct tension in the rope is ultimately identified as 515 N after recognizing the rope's angle relative to the incline is actually 10 degrees. This highlights the importance of accurately accounting for angles in physics problems involving inclined planes.
BrainMan
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Problem: a 1200-N go-cart is being pulled up a 25 degree incline by a rope that makes an angle of 35 degrees with the horizontal. Neglecting all frictional effects, determine the tension in the rope necessary to pull the cart up the incline at a constant speed

Relevant equations:
Sum of the forces= 0

Attempt: The first thing I did was find the force necessary to pull the cart at a constant speed parallel to the horizontal so sin 25= x/1200 so x= 507.14. Then I treated that number like one of the sides of a right triangle and did Cos 35= 507.14/x and got x= 618.46. The correct answer is 515 N
 
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I think you treated it like the rope was at an angle of 35 degrees relative to the cart. Actually it is only 10 degrees.
 
Ok I see my mistake. Thanks!
 
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