- #1
Apashanka
- 429
- 15
From the vector identity ##\nabla •fA=f(\nabla • A)+A•\nabla f## where f is a scalar and A is a vector.
Now if f is an operator acting on A how does this formula change??
Like ##\nabla •[(v•\nabla)v]## where v is a vector
Now if f is an operator acting on A how does this formula change??
Like ##\nabla •[(v•\nabla)v]## where v is a vector
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