Calculating the Mass Flow Rate for Point C

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The mass flow rate at point C is calculated to be 2000 kg/s using the formula mass flow rate = ρ * dV/dt, with a velocity of 50 m/s and an area of 0.04 m². The discussion highlights that while the problem provides extra information, it is essential to discern what is necessary for solving the question. At point B, which has a wider pipe, the water must flow at a different speed to maintain the same mass flow rate as at point C. The participants agree that the extra details in the problem can sometimes be misleading, but arriving at the correct answer suggests clarity in understanding the concepts. Overall, the discussion emphasizes the importance of critical thinking in problem-solving.
jimbo71
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Homework Statement


see attachment


Homework Equations


Av=dV/dt
mass flow rate =roe*dV/dt



The Attempt at a Solution


the velocity at point c is 50m/s and the area of the opening is 0.04m^2. (50m/s)(0.04m^2)(1000kg/m^3)=2000Kg/s
 

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Do you think these questions sometimes give you extra information in order for you to show that you know how to sort out the essential from the not useful?
At point B the pipe is wider than at C.
At B will the water be flowing faster, slower, or the same speed as a point C ?
Obviously the same amount of water must pass point B and point C.
So what can we say about the mass flow at B?
 
jimbo71 said:

Homework Statement


see attachment


Homework Equations


Av=dV/dt
mass flow rate =roe*dV/dt



The Attempt at a Solution


the velocity at point c is 50m/s and the area of the opening is 0.04m^2. (50m/s)(0.04m^2)(1000kg/m^3)=2000Kg/s

Looks correct to me.

CS
 
Stewart,
Yes he's right, but the question gives a lot of unnecessary detail and I was trying to see if he was misled by it.
 
I was a little mislead by the simplicity of the problem. Since the 6th grade, I've known some problems give more information than needed.
 
Carid said:
Stewart,
Yes he's right, but the question gives a lot of unnecessary detail and I was trying to see if he was misled by it.

Typically when students give the correct answer it implies that they were not mislead by it! :wink:

CS
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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