Calculating the p.d. Across EC - Get an Explanation

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To calculate the potential difference (p.d.) across points E and C, the circuit involves resistors of 2 k ohms and 1 k ohm connected to a 4 V source. The correct approach is to apply voltage division, which leads to a p.d. of 3 V across EC. The user expresses confusion over the calculations and attempts various voltage values without success. A clear method for solving such problems is needed to avoid guesswork during exams. Understanding voltage division and the arrangement of resistors is crucial for accurate calculations.
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Homework Statement


What is the p.d. across EC?



Sorry about the bad drawing.

Homework Equations





The Attempt at a Solution



I know you need to split the 4 V into the 2 k ohms, 2 k ohms and 1 kilo ohm. The answer is 3 V. I'm not sure how to get this answer. Someone explain please?
 

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What have you tried all ready? I'll help by saying that ruling out any voltage drop in the wire:

Voltage at A = Voltage at E = 4V
 
I'm really not sure. I've tried the V between C and D to be o.5 V and the V between E+F and F+G to be 1 V, but it doesn't work..

I've tried lots of other combinations too. Is there an easy way to calculate? I mean if I was in an exam this question would take me a while because all I am doing is guessing numbers.
 
(a) The polarisation pattern is elliptical with maximum (1,1) and minimum (-1,-1), and anticlockwise in direction. (b) I know the solution is a quarter-wave plate oriented π/4, and half-wave plate at π/16, but don't understand how to reach there. I've obtained the polarisation vector (cos π/8, isin π/8) so far. I can't find much online guidance or textbook material working through this topic, so I'd appreciate any help I can get. Also, if anyone could let me know where I can get more...

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