Calculating the Polarization of a Plane Wave in Electromagnetic Exercises

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SUMMARY

This discussion focuses on calculating the polarization of a plane wave represented by the complex electric field vector \(\vec{E} = (\sqrt{2}\hat{x}+\hat{y}-\hat{z})e^{-2\pi 10^6(y+z)}\). The direction of propagation is identified as \(\hat{k}= \frac{1}{\sqrt{2}}(\hat{y}+\hat{z})\). The user explores a change of basis to \(\{\hat{u},\hat{v},\hat{w}\}\) for further analysis but encounters confusion regarding the coefficients \(a\), \(b\), and \(c\). The conclusion confirms that the wave is polarized, with the polarization direction being orthogonal to the propagation direction, and suggests using a coordinate rotation for clarity.

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Hello everybody :)
I'm doing some electromagnetic exercises, but I got stuck in calculating the polarization of a plane wave.
The complex field associated to the wave is the following
\vec{E} = (\sqrt{2}\hat{x}+\hat{y}-\hat{z})e^{-2\pi 10^6(y+z)} = \hat{p}e^{-2\pi 10^6(y+z)}
It is easy to calculate that the direction of propagation is
\hat{k}= \frac{1}{\sqrt{2}}(\hat{y}+\hat{z})
but now I want to calculate if the wave is polarized and how.

If the propagation direction was along one of the axis was pretty easy, I just need to look at the components in front of the exponential. But now that I can't how can I do it?

My idea was to make a change of the basis, from \{\hat{x},\hat{y},\hat{z}\} to \{\hat{u},\hat{v},\hat{w}\} where
\hat{u} = \frac{1}{\sqrt{2}}(\hat{x}+\hat{z}) ,\quad \hat{v} = \frac{1}{\sqrt{2}}(\hat{x}+\hat{y}) ,\quad \hat{w} = \frac{1}{\sqrt{2}}(\hat{y}+\hat{z})
Then rewrite \hat{p} in this base, which became (I don't consider the square root factor, it doesn't change the result since I'm just looking how the components are related to each other)
\sqrt{2}\hat{x}+\hat{y}-\hat{z} = a\hat{u} + b\hat{v} + c\hat{w}= a (\hat{x}+\hat{z}) + b(\hat{x}+\hat{y}) + c(\hat{y}+\hat{z})

Which gives me values for all a,b and c. And that's strange (c should be zero since is a plane wave so there shouldn't be anything along this direction).

So... What's my mistake? :)
 
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The wave is polarized - I don't understand what you mean by "how" it is polarized: the polarization direction is quite clear from the vector that precedes the exponent.

The polarization is indeed orthogonal to the propagation direction as required (easily checked by taking the dot-product). If you want to rotate p so that the propagation direction lies along a principal axis, you can always employ a coordinate rotation (which is more intuitive than employing a transformation to a non-orthogonal basis set IMO).

Claude.
 
\{\hat{u},\hat{v},\hat{w}\} are not perpendicular to each other.
 

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