Calculating the Velocity and Time of a Freely Falling Rock

AI Thread Summary
To solve the problem of a rock thrown from a 30-meter building, the initial velocity is given as 18 m/s. The equations of motion are applied, leading to the calculation of the time and final velocity before impact. The correct time of flight is determined to be approximately 3.67 seconds, and the final speed just before hitting the street is about 66.04 m/s. The initial miscalculation of 9.8 seconds was clarified once the initial velocity was confirmed. Accurate application of kinematic equations is essential for solving projectile motion problems.
ThiagoG
Messages
15
Reaction score
0

Homework Statement


A small rock is thrown vertically upward with a speed of
from the edge of the roof of a 30.0-m-tall building. The
rock doesn’t hit the building on its way back down and lands in the
street below. Air resistance can be neglected. (a) What is the speed
of the rock just before it hits the street? (b) How much time elapses
from when the rock is thrown until it hits the street?


Homework Equations


0=30+18t-4.9t2
Vx=30-9.8t


The Attempt at a Solution


For the time I got 9.8s and for the velocity I got -66.04 m/s. I'm not sure where I went wrong.
 
Physics news on Phys.org
You didn't provide the initial velocity.
 
Lamebert said:
You didn't provide the initial velocity.

Sorry about that. The initial velocity is 18 m/s.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top