Calculating the voltage at a certain Resistor

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    Resistor Voltage
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Discussion Overview

The discussion revolves around calculating the voltage across a specific resistor (R3) in a circuit when a switch (S1) is closed. Participants explore different methods for solving the problem, including the use of voltage dividers and Ohm's Law, while addressing the implications of parallel and series resistor combinations.

Discussion Character

  • Technical explanation
  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant calculates the voltage at R1 using a loaded voltage divider approach, arriving at a voltage of 5.65V for both R2 and R3.
  • Another participant suggests a more systematic method involving simplifying the circuit, calculating total resistance, and then using Ohm's Law to find the voltage, but encounters discrepancies in their results.
  • Concerns are raised about determining the current through R3 and R2, with a suggestion to calculate the voltage drop across R1 first and then find the remaining voltage for the parallel combination of R2 and R3.
  • A later reply confirms the need to use the parallel resistance of R2 and R3 to arrive at the correct voltage drop across R3.

Areas of Agreement / Disagreement

Participants express differing views on the methods for calculating the voltage across R3, with some advocating for the voltage divider approach and others emphasizing the importance of correctly applying Ohm's Law and considering parallel resistances. The discussion remains unresolved regarding the best method to use.

Contextual Notes

There are limitations in the assumptions made about current distribution in the circuit, and the discussion highlights the complexity of applying different methods to arrive at consistent results.

arhzz
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Homework Statement
Calculate the voltage at the Resistor R3 when S1 closses
Relevant Equations
U=RI
Hello!

Consider this circuit;

ce se rasprsnem.png


Now the value are given as follows; U = 10V; R1 = 150 Ohm R2 = 470 Ohm R3 = 330 Ohm;

I am susposed to calculate the voltage at R1 when S1 clossed;so when there is a current flowing through it.

I did that using the loaded voltage divider,since I can see that R2 and R3 are parallel and than in series with R1 so I used the formula;

$$ U2 = U * \frac{R2||R3}{R1+R2||R3} $$ and that should give me that U2 = 5,65 V and since U2 is parallel to U3 the voltages are the same so U3 = 5,65V.

Pretty sure that is correct,at least according to my solutions.

But here is the question I had.Whenever I googled or really though about solving a relatively simple circuit where I need to calculate the voltage at a certain resistor there would always come up the following method.

1. You simplify the circuit as much as possible (parallel,series circuits etc.)
2.Then you find the total Resistance of the circuit.
3.Find the total current flowing through it;
4. Than use Ohm's Law to find the voltage

I tried using that here but it doesn't seem to work,and I don't know why. Here is how I tried.

So first I calculated the total resitance; ## R_total = 343,875 Ohm ## R2 and R3 are parallel in series with R1;

Than since I know the voltage (10V) I calculated the current flowing through the circuit; ## I = \frac{U}{R_total} ## Should be I = 0,029A

And than I used Ohm's Law to get U3;

U3 = I * R3 = 9,57V

That is not right.So my question is why cannt I use this "method" to calculate the voltage (or voltage drop) across R3,even though this is,if you google it or try looking it up the way that these problems are suggested to be solved.Many thanks!
 
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arhzz said:
Homework Statement:: Calculate the voltage at the Resistor R3 when S1 closses
Relevant Equations:: U=RI

And than I used Ohm's Law to get U3;

U3 = I * R3 = 9,57V
You forgot to use the parallel combination here...
 
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How do you know how much current goes through ##R_3## and how much through ##R_2##? You are not using the correct current for ##R_3##.
Alternatively, now that you know the current through ##R_1##, you can calculate the voltage drop across it and subtract that from 10V to get the remaining voltage drop across the ##R_2, R_3## combination.
 
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Yes of course I need to multiply with the parallel resistance of R2 and R3.It worked obviously.

That with the voltage drop is also a way,thanks for the insight and help!

Cheers!
 
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