Calculating the Volume of a Spherical Cap - A Quick Guide

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Homework Help Overview

The discussion revolves around calculating the volume of a spherical cap, a topic within the subject area of calculus and geometry. Participants are exploring the differences between a spherical cap and a hemisphere, as well as methods for finding volumes using integrals.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants question the distinction between a spherical cap and a hemisphere. Others discuss the use of calculus and integrals, mentioning methods involving "disks" and spherical coordinates.

Discussion Status

The discussion includes various interpretations of the problem, with some participants providing mathematical formulations and others seeking clarification on assumptions. There is no explicit consensus, but productive lines of reasoning have been shared.

Contextual Notes

Participants are reminded to show their work before receiving help, indicating a focus on the learning process. There is an emphasis on maintaining posts for the benefit of others who may have similar questions.

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ok i think I've got it. thanks
 
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You need to show your work before you get help. What are your thoughts/ideas on this problem?
 
I do not think that there is any difference between a "spherical cap" and a hemisphere.

Finding a volume using calculus generally involves an integral, there are several methods which can be used to solve such a problem. Do you recall seeing something having to do with "disks"?
 
Let F defined on [0,r]x[0,2\pi]x[0,\pi] by
F(R, S, T)=(R\cos(S)\sin(T), R\sin(S)\sin(T), R\cos(T))
(the change into spherical coordinates).
The absolute value of its Jacobian is R^2\sin(T).

Your domain of integration (cap) is defined by
{(x, y, z) : x^2 + y^2 + z^2 \leq r^2 , r-h \leq z \leq r}
and its pre-image through F is
D=[0,r]x[0,2\pi]x[0,T_0],
where T_0 satisfies \cos(T_0)=(r-h)/r=1-h/r.

Volume = \int_{D}R^2\sin(T)dRdSdT
= (\int_0^rR^2dR).(\int_0^{2\pi}dS).(\int_…
= 1/3r^3.2\pi.(1-\cos(T_0)) = 2\pi.h.r^2/3.
QED.
 
Please do not erase a post after it has been resolved! Other people are sure to have the same question and can still learn from thread.
 

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