Surface area of a spherical cap

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Homework Help Overview

The discussion revolves around calculating the area of a circle on the surface of a sphere, specifically focusing on the surface area of a spherical cap and its behavior when the radius of the base of the cap is much smaller than the radius of the sphere.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use calculus and double integrals in spherical coordinates to derive the area but encounters difficulties. They also explore the relationship between the surface area of a spherical cap and the limit where the radius of the base is small compared to the sphere's radius.

Discussion Status

Participants have provided insights regarding the use of Taylor series to approximate cosine terms in the integral. There is acknowledgment of the original poster's challenges, and some guidance has been offered to simplify the problem, though no consensus has been reached on a definitive solution.

Contextual Notes

The original poster notes that they have not been able to derive a formula that incorporates both the radius of the cap and the radius of the sphere effectively. There is an emphasis on the need for approximations when dealing with small values of the radius relative to the sphere.

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Homework Statement


Calculate the area of a circle of radius r (distance from center to circumference) in the two-dimensional geometry that is the surface of a sphere of radius a. Show that this reduces to πr2 when r << a


Homework Equations


Surface area of a spherical cap = 2πah = π(r2 + h2)


The Attempt at a Solution


I've thrown all the calculus I've known at this problem and couldn't crack it. I immediately realized this problem was trying to get me to calculate the area of a spherical cap in the limit where the radius of the base of the cap was much smaller than the radius of the sphere, but I tried a straightforward double integral in spherical coordinates and couldn't get it to come out right. I tried to same thing integrating over infinitesimally thin rings from the top of the sphere to the circumference of the circle. No dice. I even found the surface area for the spherical cap, which I posted above, and attempted to just show that it reduced to πr2 when r << a and couldn't even prove that much. I couldn't get a formula with r and a together. None of the handfuls of derivations I found for the surface area of a spherical cap helped me.
 
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The surface area integral you performed should have a cosine term in it if you used spherical coordinates, specifically cos(r/a). The entire formula should only contain a and r as variables. Replace the cosine term by the 2nd degree Taylor polynomial for cosine about r/a = 0 to get an approximation of cosine for small values of r/a that have negligible 4th degree and higher contributions. The formula should then immediately simplify to πr2.
 
Last edited:
How about finding the surface of revolution of a circle's arc?
 
slider142 said:
The surface area integral you performed should have a cosine term in it if you used spherical coordinates, specifically cos(r/a). The entire formula should only contain a and r as variables. Replace the cosine term by the 2nd degree Taylor polynomial for cosine about r/a = 0 to get an approximation of cosine for small values of r/a that have negligible 4th degree and higher contributions. The formula should then immediately simplify to πr2.

That's it. I simply forgot to expand into the second term of the Taylor series. My friend in the class came along while I was in the library and alerted me of this earlier today. Thanks for the help!
 

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