Calculating Thrust and Lift Forces for a Jet Fighter Taking Off at 27 Degrees

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The discussion revolves around calculating the thrust and lift forces for a jet fighter taking off at an angle of 27 degrees with the horizontal, while accelerating at 2.62 m/s². The weight of the plane is given as 79,300 N.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between thrust and lift forces, questioning the use of trigonometric functions to resolve these forces. There is discussion about the total force acting on the plane and how to account for acceleration and weight.

Discussion Status

Participants are actively engaging with the problem, raising various interpretations and calculations regarding thrust and lift. Some guidance has been offered regarding the forces acting on the plane, but there is no explicit consensus on the correct approach or final values.

Contextual Notes

There are indications of differing answers among participants, suggesting potential confusion or misinterpretation of the problem setup. The discussion includes considerations of the forces involved and their directions, as well as the implications of the plane's acceleration.

Anisotropic Galaxy
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A jet fighter takes off at an angle of 27.0 degrees w/ the horizontal, accelerating at 2.62 m/s*s. The plane weighs 79,300 N. I need to find the thrust T of the engine on the plane and the lift force L exerted by the air perpendicular to the wings.

Thanks

My reasoning so far...

79,3000 N / g = 8084 kg.

F = ma = 2.62 m/s^2 * 8092 kg -> 21179 N.

So I'm thinking that be the thrust.

As for the lift force L though, I don't know. Could I use sin or cosine?
 
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Anisotropic Galaxy said:
A jet fighter takes off at an angle of 27.0 degrees w/ the horizontal, accelerating at 2.62 m/s*s. The plane weighs 79,300 N. I need to find the thrust T of the engine on the plane and the lift force L exerted by the air perpendicular to the wings.

Thanks

My reasoning so far...

79,3000 N / g = 8084 kg.

This is the mass of the airplane. You'll need it.

Here's a list of all the forces that act upon the plane:
- gravity
- lift of the wings
- thrust of the engines

That's 3 forces (try to find in what direction they are applied ; make a drawing of the forces). Find the total force.

Now, the airplane is not in equilibrium. It is accelerating. So what should you do with the 3 forces ? What equation should you use ? (hint: Newton...)

F = ma = 2.62 m/s^2 * 8092 kg -> 21179 N.

That should be the total force, yes...

So I'm thinking that be the thrust.

As for the lift force L though, I don't know. Could I use sin or cosine?

No, it is not the thrust. It is the total force (of which thrust is only a part)...

Leave you here...
 
Is the thrust simply cos(27.0)*21179 N then?

So...the force of the lift is 89,000 N, right? a_y = 2.62 m/s^2*sin27.0 = (Lift - mg)/m so then by substituting things, Lift = 89,000 N.
 
But someone else got a different answer than me, so I'm probably wrong here...
 
Does


Should i switch the axis around, and then the Force of the thrust = (2.62cos27-gsin27)m and L equal to (2.62sin27+gcos27)m?

sound right...?
 
or.. maybe not?

L = mgcos27 and T = m(a_x) + mgsin27?
 

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