Calculating Time for Bolt to Fall in Elevator with Constant Acceleration

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The problem involves an elevator ascending with a constant acceleration of 1.2 m/s², where a bolt falls from the ceiling 2 seconds after the elevator starts. The initial speed of the bolt, which is equal to the elevator's speed at that moment (2.4 m/s), must be considered in the calculations. The equation used to find the time it takes for the bolt to hit the elevator floor is incorrect because it neglects this initial velocity. By incorporating the bolt's initial speed, the correct time for the bolt to hit the floor can be determined, which is 0.7 seconds.
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Homework Statement



It's a question from IE Irodov's General Physics -->

An elevator car whose floor to ceiling is equal to 2.7m starts ascending with constant acceleration 1.2m/s2. 2s after the start a bolt begins to fall from the ceiling of the car .Find

(a) the time after which bolt hits the floor of the elevator.

It's only the first part of the problem ...

Homework Equations





The Attempt at a Solution



After two seconds of start, the elevator catches a speed of v = 2.4 m/s ...
Then, I assumed that after t seconds the event of bolt falling on floor occurs ...

So the elevator floor covers a distance of 2.4t + 1/2at2
And the bolt covers 1/2gt2

Using some intution, I got

2.4t + 1/2at2 + 1/2gt2 = 2.7
Solving it, my answer comes out t = 0.5 seconds but the answer is 0.7.

Please don't solve it using relative speed of bolt with respect to elevator or any other method... just let me know what's wrong with my solution.
 
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physics kiddy said:
So the elevator floor covers a distance of 2.4t + 1/2at2
OK.

And the bolt covers 1/2gt2
You neglected the initial speed of the bolt. This assumes it's dropped from rest.

Correct that and you'll get the right answer.
 
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