Calculating Time for Rectangular Block to Stop on Rough Ground

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SUMMARY

The discussion focuses on calculating the time it takes for a rectangular block to stop when transitioning from a smooth surface to rough ground with a coefficient of friction (μ). The deceleration of the block is defined as a = μg when the entire block is on the rough ground. The solution involves applying kinematic equations to relate initial velocity (u), distance (s), and time (t). The key equations used include v² - u² = 2as and s = ut + 0.5at², leading to a definitive method for determining the stopping time.

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Homework Statement


A rectangular block of length L is traveling on a smooth surface at velocity u. When it encounters rough ground with coefficient of friction mu, it decelerates to a stop. What is the time taken for the rectangular block to stop?

Homework Equations


F= (mu)mg

The Attempt at a Solution


Deceleration of the block is given by a = (mu)gx/L if only part of the block is on the rough ground. If the entire block is on the rough ground, the maximum deceleration is given by a = (mu)g. This means i have to split the question into two cases.
1. time taken when x is less than or equal to L
2. time taken when x is greater than L

But I am stuck here. I don't know how to relate x to t and u.
 
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Friction force is independent of area of contact. So I think there is no need for taking a part of the block.

deceleration of the block is (mu)g
apply kinematics equation
v^2 - u^2 =2as
v=0 s=L
find a relation between u and s from here
use another equation - s=ut +0.5at^2
find out time from this equation. ( here discriminant will become 0 from previous equation.)
 

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